Answered

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Can someone help with number 4 please

Can Someone Help With Number 4 Please class=

Sagot :

AL2006
The way I look at these things is like this:

-- The runner covered 12 meters in 4 seconds.
Average speed = 3 meters per second.

-- Speed at the beginning = zero.
In order to make the average 3, Speed at the end = 6 meters per second.

-- Speed increased from zero to 6 meters per second in 4 seconds.
It must have increased 1.5 meters per second each second.

That's choice-#2.
sairah
Here we have - 
Acceleration (a) = ?
Initial velocity (u) = 0 m/s (runner starts from rest)
Distance (s) = 12 m
Time (t) = 4 seconds

So, using the second equation of motion, we have-

[tex]s = ut + \frac{1}{2}at^{2} [/tex]

[tex]12 = 0*4 + \frac{1}{2}*a*4 ^{2} [/tex]

[tex]12 = 0+8a[/tex]

[tex] \frac{12}{8} = a[/tex]

[tex]1.5m/ s^{2} [/tex]

So, option (2) is correct.
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