Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Can someone help with number 4 please

Can Someone Help With Number 4 Please class=

Sagot :

AL2006
The way I look at these things is like this:

-- The runner covered 12 meters in 4 seconds.
Average speed = 3 meters per second.

-- Speed at the beginning = zero.
In order to make the average 3, Speed at the end = 6 meters per second.

-- Speed increased from zero to 6 meters per second in 4 seconds.
It must have increased 1.5 meters per second each second.

That's choice-#2.
sairah
Here we have - 
Acceleration (a) = ?
Initial velocity (u) = 0 m/s (runner starts from rest)
Distance (s) = 12 m
Time (t) = 4 seconds

So, using the second equation of motion, we have-

[tex]s = ut + \frac{1}{2}at^{2} [/tex]

[tex]12 = 0*4 + \frac{1}{2}*a*4 ^{2} [/tex]

[tex]12 = 0+8a[/tex]

[tex] \frac{12}{8} = a[/tex]

[tex]1.5m/ s^{2} [/tex]

So, option (2) is correct.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.