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How do I solve for x and state the restriction if (a-c)/(x-a)=m

Sagot :

[tex]\frac{a-c}{x-a}=m;\ D:x\neq a\\\\m(x-a)=a-c\\\\mx-ma=a-c\\\\mx=a-c+ma\ \ \ \ /:m\neq0\\\\x=\frac{a-c+ma}{m}[/tex]
kayt91

[tex] \frac{a - c}{x - a} = m [/tex]

[tex] (x - a) \frac{a - c}{x - a} = m ( x - a) [/tex]

[tex] a - c = mx - am [/tex]

[tex] a - c + am = mx [/tex]

[tex] \frac{a}{m} - \frac{c}{m} + \frac{am}{m} = x [/tex]

[tex] \frac{a - c}{m} + a = x [/tex]

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