bulldog75stp
Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

White phosphorus, P4, is prepared by fusing
calcium phosphate, Ca3(PO4)2, with carbon, C,
and sand, SiO2, in an electric furnace.



2Ca3(PO4)2(s) + 6SiO2(s)
+ 10C(s) --> P4(g)
+ 6CaSiO3(l) + 10CO(g)



How many grams of calcium phosphate are required to give
30.0 g of phosphorus?

Think it's 150. g Ca3(PO4)2 (am I right or wrong? Please explain, thanks) 

Sagot :

pyromorphite
2Ca3(PO4)2 + 6SiO2 + 10C ---> P4 + 6CaSiO3 + 10CO

1 mole of Ca3(PO4)2 = 310g
1 mole of P4 = 124g

according to the reaction:
2*310g Ca3(PO4)2----------------124g P4
x g Ca3(PO4)2 ------------------------ 30g P4
x = 150g Ca3(PO4)2

so, your answer is good
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.