Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

At 10a.m. Juan leaves the city traveling north at 60 mi/hr. One hour later mel leaves the city traveling south at 50 mi/hr. At what time will they be 830 miles apart?

Sagot :

kayt91

[tex] \frac{60}{1} = \frac{830}{x} [/tex]
[tex] 60x = 830 [/tex]
[tex] x = 13.83 [/tex]
[tex] 10 + 13.83 = 23.83 [/tex]
23.83 hours is around 11:50pm

[tex] \frac{50}{1} = \frac{830}{x} [/tex]
[tex] 50x = 830 [/tex]
[tex] x = 16.6 [/tex]
[tex] 11 + 16.6 = 27.6 [/tex]
[tex] 27.6 - 24 = 3.6 [/tex]
3.6 is around 1:36am

AL2006
-- At 11 AM, when Mel starts out, Juan has already covered 60 miles.

-- After that, since they're traveling in opposite directions, the distance
between them increases (60 + 50) = 110 miles every hour.

Let's call 'H' the number of hours after 11 AM.
Then the distance between them is

D = 110H + 60

When is this distance 830 miles ?  Wouldn't you like to know !

830 = 110H + 60

Subtract 60 from each side:

770 = 110H

Divide each side by 110 :

H = 770 / 110 = 7 .

It happens 7 hours after 11 AM.
That would be 6:00 PM .
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.