Answered

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I need to find the zeros of the function:

f(x)=2x^2-5x-3

Sagot :

konrad509
[tex]2x^2-5x-3=0\\ 2x^2-2x-3x-3=0\\ 2x(x+1)-3(x+1)=0\\ (2x-3)(x+1)=0\\ x=\frac{3}{2} \vee x=-1[/tex]
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