At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Here are the steps you would need to follow:
#1). Define what 'the 'X is, and how it's related to the ball.
#2). Be clear on how 'the X' is related to the 'known velocity'.
#3). Identify how the 'known velocity' is related to the action of the ball when it's launched.
With this information in front of you, you'll have a much better chance
of answering the question.
With none of it in front of me, I have no chance at all.
#1). Define what 'the 'X is, and how it's related to the ball.
#2). Be clear on how 'the X' is related to the 'known velocity'.
#3). Identify how the 'known velocity' is related to the action of the ball when it's launched.
With this information in front of you, you'll have a much better chance
of answering the question.
With none of it in front of me, I have no chance at all.
Use the equation:
[tex]X=ut+ \frac{1}{2} at^{2} [/tex]
where u is the initial velocity, a is the acceleration downwards (in this case [tex]a=g=9.81m s^{-2} [/tex])
Hope this helps :)
[tex]X=ut+ \frac{1}{2} at^{2} [/tex]
where u is the initial velocity, a is the acceleration downwards (in this case [tex]a=g=9.81m s^{-2} [/tex])
Hope this helps :)
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.