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Answered

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A 10.0-milliliter sample of NaOH(aq) is neutralized by 40.0 milliliters of 0.50 M HCl. What is the molarity of the NaOH(aq)?

Sagot :

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[tex] \frac{10 mL}{1000 mL} = 0.01 L[/tex]

[tex] \frac{40mL}{1000mL} =0.04L[/tex]

[tex]M _{1} V_{1}=M_{2}V_{2}[/tex]

[tex]M_{1}(0.01)=(0.50)(0.04)[/tex]

[tex]M_{1}(0.01)=0.02[/tex]

[tex]M_{1}= \frac{0.02}{0.01} [/tex]

[tex]M_{1}=2[/tex]
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