honeyrodianne
Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

1. (k+7)² =289
2. (2s-1)² =225
3. (x-4)² =169

please help me answer these :)

Sagot :

konrad509
[tex](k+7)^2 =289\\ |k+7|=17\\ k+7=17\vee k+7=-17\\ k=10 \vee k=-24[/tex]

[tex] (2s-1)^2 =225\\ |2s-1|=15\\ 2s-1=15\vee 2s-1=-15\\ 2s=16 \vee 2s=-14\\ s=8 \vee s=-7[/tex]

[tex](x-4)^2 =169\\ |x-4|=13\\ x-4=13 \vee x-4=-13\\ x=17 \vee x=-9[/tex]
kate200468
[tex]1. \ \ \ (k+7)^2 =289\\\\\Leftrightarrow\ \ \ k+7= \sqrt{289} \ \ \ or\ \ \ \ k+7=- \sqrt{289}\\\\k=17-7=10\ \ \ \ \ \ \ or\ \ \ \ k=-17-7=-24 \\\\2.\ \ \ (2s-1)^2 =225\\\\\Leftrightarrow\ \ \ 2s-1= \sqrt{225} \ \ \ or\ \ \ \ 2s-1=- \sqrt{225}\\\\2s=15+1\ \ \ \ \ \ \ or\ \ \ \ 2s=-15+1\\2s=16\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ 2s=-14\\s=8\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ s=-7 \\\\[/tex]

[tex]3.\ \ \ (x-4)^2 =169\\\\\Leftrightarrow\ \ \ x-4= \sqrt{169} \ \ \ or\ \ \ \ x-4=- \sqrt{169}\\\\x=13+4=17\ \ \ \ \ \ \ or\ \ \ \ x=-13+4=-9[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.