honeyrodianne
Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

1. (k+7)² =289
2. (2s-1)² =225
3. (x-4)² =169

please help me answer these :)

Sagot :

konrad509
[tex](k+7)^2 =289\\ |k+7|=17\\ k+7=17\vee k+7=-17\\ k=10 \vee k=-24[/tex]

[tex] (2s-1)^2 =225\\ |2s-1|=15\\ 2s-1=15\vee 2s-1=-15\\ 2s=16 \vee 2s=-14\\ s=8 \vee s=-7[/tex]

[tex](x-4)^2 =169\\ |x-4|=13\\ x-4=13 \vee x-4=-13\\ x=17 \vee x=-9[/tex]
kate200468
[tex]1. \ \ \ (k+7)^2 =289\\\\\Leftrightarrow\ \ \ k+7= \sqrt{289} \ \ \ or\ \ \ \ k+7=- \sqrt{289}\\\\k=17-7=10\ \ \ \ \ \ \ or\ \ \ \ k=-17-7=-24 \\\\2.\ \ \ (2s-1)^2 =225\\\\\Leftrightarrow\ \ \ 2s-1= \sqrt{225} \ \ \ or\ \ \ \ 2s-1=- \sqrt{225}\\\\2s=15+1\ \ \ \ \ \ \ or\ \ \ \ 2s=-15+1\\2s=16\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ 2s=-14\\s=8\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ s=-7 \\\\[/tex]

[tex]3.\ \ \ (x-4)^2 =169\\\\\Leftrightarrow\ \ \ x-4= \sqrt{169} \ \ \ or\ \ \ \ x-4=- \sqrt{169}\\\\x=13+4=17\ \ \ \ \ \ \ or\ \ \ \ x=-13+4=-9[/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.