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 If 3∈A and 3B, then which of the following statements is not true?


A: 3 is an element of B complement.
B: 3 is an element of A∪B.
C: 3 is an element of A∩B.

Sagot :

[tex]3\in A\ \wedge\ 3\notin B\ then:\\\\A\ is\ true\\\\B\ is\ true\\\\B\ is\ not\ true\ because\ if\ 3\in A\ \wedge\ 3\notin B\ then\ 3\in A\ \wedge\ 3\in B[/tex]

Answer:

Option A and C are not true.

Step-by-step explanation:

As shown in Venn diagram attached

A. 3∉B which states 3 is the element which doesn't belong to B so this option is not true.

B. 3∈(A∪B)

Since 3∈A and 3∉B therefore 3∈(A∪B)

Statement is true.

C. 3∈A and 3∉B so 3∉(A∩B) because 3 is not the common element of A∩B.

Therefore this option is not true.

Therefore Options A and C are not true.

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