Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
[tex]3\in A\ \wedge\ 3\notin B\ then:\\\\A\ is\ true\\\\B\ is\ true\\\\B\ is\ not\ true\ because\ if\ 3\in A\ \wedge\ 3\notin B\ then\ 3\in A\ \wedge\ 3\in B[/tex]
Answer:
Option A and C are not true.
Step-by-step explanation:
As shown in Venn diagram attached
A. 3∉B which states 3 is the element which doesn't belong to B so this option is not true.
B. 3∈(A∪B)
Since 3∈A and 3∉B therefore 3∈(A∪B)
Statement is true.
C. 3∈A and 3∉B so 3∉(A∩B) because 3 is not the common element of A∩B.
Therefore this option is not true.
Therefore Options A and C are not true.

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.