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Sagot :
[tex]3\in A\ \wedge\ 3\notin B\ then:\\\\A\ is\ true\\\\B\ is\ true\\\\B\ is\ not\ true\ because\ if\ 3\in A\ \wedge\ 3\notin B\ then\ 3\in A\ \wedge\ 3\in B[/tex]
Answer:
Option A and C are not true.
Step-by-step explanation:
As shown in Venn diagram attached
A. 3∉B which states 3 is the element which doesn't belong to B so this option is not true.
B. 3∈(A∪B)
Since 3∈A and 3∉B therefore 3∈(A∪B)
Statement is true.
C. 3∈A and 3∉B so 3∉(A∩B) because 3 is not the common element of A∩B.
Therefore this option is not true.
Therefore Options A and C are not true.

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