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Sagot :
[tex]\left\{\begin{array}{ccc}x+y=251\\y=x+41\end{array}\right\\\\substitute:\\\\x+x+41=251\\2x+41=251\ \ \ \ /-41\\2x=210\ \ \ /:2\\x=105\\\\y=105+41=146\\\\Answer:105\ and\ 146.[/tex]
146 dan 105
Further explanation
Given:
Two numbers add to 251 and the second is 41 bigger than the first.
Question:
What are the two numbers?
The Process:
Let the first number we call x, and the second number is y.
Two numbers add to 251, We arrange it as Equation-1:
[tex]\boxed{ \ x + y = 251 \ }[/tex]
The second is 41 bigger than the first. We arrange it as Equation-2:
[tex]\boxed{ \ x = y + 41 \ } \ or \ \boxed{ \ x - y = 41 \ }[/tex]
Let us solve the two equations above by eliminating the same variable. With the addition process, it appears that the variable y will be eliminated.
x + y = 251
x - y = 41
-------------- ( + )
2x = 292
Divide by two on both sides.
x = 146
The final step is to determine the variable y with the substitution of the value x into one of the two equations above. We choose Equation-1.
x = 146 → 146 + y = 251
y = 251 - 146
y = 105.
Thus, the two numbers are 146 and 105.
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