Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
[tex]2x^2 + 6x + 5 = 0[/tex]
[tex]x= \frac{-b+/- \sqrt{b^2 -4ac} }{2a} [/tex]
[tex]x= \frac{-(6)+/- \sqrt{(6)^2 -4(2)(5)} }{2(2)} [/tex]
[tex]x= \frac{-6+/- \sqrt{36 -40} }{4} [/tex]
[tex]x= \frac{-6+/- \sqrt{-4} }{4}[/tex]
[tex]x= \frac{-6+/- i\sqrt{4} }{4}[/tex]
[tex]x= \frac{-6+/- 2i }{4}[/tex]
NO REAL ROOTS
[tex]x= \frac{-b+/- \sqrt{b^2 -4ac} }{2a} [/tex]
[tex]x= \frac{-(6)+/- \sqrt{(6)^2 -4(2)(5)} }{2(2)} [/tex]
[tex]x= \frac{-6+/- \sqrt{36 -40} }{4} [/tex]
[tex]x= \frac{-6+/- \sqrt{-4} }{4}[/tex]
[tex]x= \frac{-6+/- i\sqrt{4} }{4}[/tex]
[tex]x= \frac{-6+/- 2i }{4}[/tex]
NO REAL ROOTS
[tex]2x^2+6x+5=0\ \ \ \ /:2\\\\x^2+3x+2.5=0\\\\x^2+2x\cdot1.5=-2.5\\\\x^2+2x\cdot1.5+1.5^2-1.5^2=-2.5\\\\(x+1.5)^2-2.25=-2.5\\\\(x+1.5)^2=-2.5+2.25\\\\(x+1.5)^2=-0.25 < 0\ aren't\ real\ roots\ because\ for\ x\in\mathbb{R},\ a^2\geq0[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.