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Sagot :
As we know that K.E = 1/2 mv² so
by arranging it
K.E ×2÷6 = v²
now by putting values
v²=13.33 m²/s²
so
v= 3.65 m/s....
by arranging it
K.E ×2÷6 = v²
now by putting values
v²=13.33 m²/s²
so
v= 3.65 m/s....
The formula to find kinetic energy is -
[tex]K.E. = \frac{1}{2}*m* v^{2} [/tex]
Where,
[tex]m = mass[/tex]
and
[tex]v = velocity[/tex]
So, putting the values in the formula we get -
[tex]40 = \frac{1}{2} *6*v^{2} [/tex]
[tex] \frac{40}{3} = v^{2} [/tex]
[tex] \sqrt \frac{40}{3} = 3.6514 m/s[/tex]
[tex]K.E. = \frac{1}{2}*m* v^{2} [/tex]
Where,
[tex]m = mass[/tex]
and
[tex]v = velocity[/tex]
So, putting the values in the formula we get -
[tex]40 = \frac{1}{2} *6*v^{2} [/tex]
[tex] \frac{40}{3} = v^{2} [/tex]
[tex] \sqrt \frac{40}{3} = 3.6514 m/s[/tex]
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