Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

how many moles of CO2 form when 58.0 g of butane, C4H10, burn in oxygen? 2C4H10+13O2--->8CO2+10H2O

Sagot :

pyromorphite
2C4H10 + 13O2 ---> 8CO2 + 10H2O 1 mole of C4H10 = 58g According to the reaction: 2*58g of C4H10 ------------- 8 molesof CO2 58g of C4H10 ----------------- x moles of CO2 x = 4 miles od CO2

Answer: 4 moles of [tex]CO_2[/tex] are produced.

Explanation:

To calculate the number of moles, we use the formula:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

For butane:

Given mass of butane = 58g

Molar mass of butane = 58 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of butane}=\frac{58g}{58g/mol}=1mole[/tex]

For the given chemical equation:

[tex]2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 1 mole of butane will produce = [tex]\frac{8}{2}\times 1=4moles[/tex] of carbon dioxide

Hence, 4 moles of [tex]CO_2[/tex] are produced.

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.