nhievher
Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

the earth rotates about its axis once every 23 h 56 min 4 s, and the radius of the earth is 3960 mile. find the linear speed of a point on the equator in mi/h

Sagot :

[tex]23h\ 56min\ 4s=\left(23+\frac{56}{60}+\frac{4}{3600}\right)h=\left(\frac{82800}{3600}+\frac{3360}{3600}+\frac{4}{3600}\right)h\\\\=\frac{86164}{3600}h\approx23.93h\\\\L=2\pi R;\ R=3960mi\to L=2\pi\cdot3960mi=7920\pi mi\approx7920\cdot3.14mi\\\\=24868.8mi\\\\v=\frac{24868.8}{23.93}\ mi/h\approx1039.231\ mi/h\leftarrow answer[/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.