paw32diamond
Answered

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Solve the inequality
2(3x-2)>_22

Sagot :

AL2006
2(3x - 2) > 22

Expand (eliminate parentheses on) the left side:

6x - 4 > 22

Add 4 to each side:

6x > 26

Divide each side by 6 :

x > 13/3
[tex]2(3x-2) \geq22\ \ \ \ /:2\\\\3x-2\geq11\ \ \ /+2\\\\3x\geq13\ \ \ \ /:3\\\\x\geq4\frac{1}{3}\\\\x\in\left<4\frac{1}{3};\ \infty\left)[/tex]

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[tex]2(3x-2) > 22\ \ \ \ /:2\\\\3x-2 > 11\ \ \ /+2\\\\3x > 13\ \ \ \ /:3\\\\x > 4\frac{1}{3}\\\\x\in\left(4\frac{1}{3};\ \infty\left)[/tex]

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[tex]2(3x-2) > -22\ \ \ \ /:2\\\\3x-2 > -11\ \ \ \ /+2\\\\3x > -9\ \ \ \ /:3\\\\x > -3\\\\x\in(-3;\ \infty)[/tex]
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