Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
[tex]\sqrt{50x^2}:\sqrt{32x^2}=\sqrt\frac{50x^2}{32x^2}=\sqrt{\frac{25}{16}}=\frac{5}{4}[/tex]
The quotient equivalent to the expression [tex]\sqrt{50x^3} \div \sqrt{32x^2}[/tex] is (5√x)/4.
Hence option B is the right choice.
How to find the quotient of an expression?
To find the quotient of an expression, we simplify the numerators and the denominators and then cancel off the like terms.
How to solve the question?
In the question, we are asked to find the equivalent expression to the quotient given by [tex]\sqrt{50x^3} \div \sqrt{32x^2}[/tex] .
To find the equivalent expression, we need to simplify the given quotient as follows:
{√(50x³)}/{√(32x²)}
= {√(25.2.x².x)}/{√(16.2.x²)} [Since, 50x³ = 25.2.x².x, and 32x² = 16.2.x²]
= {√(5².2.x².x)}/{√(4².2.x²)} [Since, 25 = 5², and 16 = 4²]
= (5x.√2.√x)/(4x√2) [Since, √(ab) = √a√b, and √a² = a]
= (5√x)/4 [Cancelling the like terms √2 and x].
Thus, the equivalent expression is (5√x)/4.
Thus, the quotient equivalent to the expression [tex]\sqrt{50x^3} \div \sqrt{32x^2}[/tex] is (5√x)/4. Hence option B is the right choice.
The question provided is incomplete. The complete question is provided in the attachment.
Learn more about finding quotients at
https://brainly.com/question/409874
#SPJ2

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.