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Sagot :
[tex]\sqrt{7x^3}:\sqrt{x}=\sqrt\frac{7x^3}{x}=\sqrt{7x^2}=x\sqrt7\\\\\sqrt{7x^3}\to x^3\geq0\to x\geq0\ \wedge\ \sqrt{x}\to x > 0\\\\Answer:D.\ x\sqrt7\ when\ x > 0[/tex]
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