Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Log (10-4x) = log (10-3x)

Sagot :

[tex]D:\\10-4x > 0\ \wedge\ 10-3x > 0\\-4x > -10\ \vee\ -3x > -10\\\\x < \frac{10}{4}\ \wedge\ x < \frac{10}{3}\\\\x < 2\frac{1}{2}\ \wedge\ x < 3\frac{1}{3}\\\\x\in(-\infty;\ 2\frac{1}{2})[/tex]


[tex]log(10-4x)=log(10-3x)\iff10-4x=10-3x\\\\-4x+3x=10-10\\\\-x=0\ \ \ /\cdot(-1)\\\\x=0\in D\\\\Solution:x=0[/tex]
konrad509
[tex]\log (10-4x) = \log (10-3x) \\ D:10-4x>0 \wedge 10-3x>0\\ D:4x<10 \wedge 3x<10\\ D:x<2.5 \wedge x<3\frac{1}{3}\\ D:x<2.5\\ 10-4x=10-3x\\ x=0[/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.