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When lithium reacts with bromine to form the compound LiBr each lithium atom
(1) gains one electron and becomes a negatively charged ion
(2) gains three electrons and becomes a negatively charged ion
(3) loses one electron and becomes a positively charged ion
(4) loses three electrons and becomes a positively charged ion

Sagot :

pyromorphite
(1) gains one electron and becomes a negatively charged ion
(2) gains three electrons and becomes a negatively charged ion
(3) loses one electron and becomes a positively charged ion
(4) loses three electrons and becomes a positively charged ion

Answer: (3) loses one electron and becomes a positively charged ion

Explanation:

Lithium bromide is formed by combination of lithium cation and bromine anion.

Electronic configuration of lithium:

[tex][Li]=1s^22s^1[/tex]

Lithium atom will loose one electron to gain noble gas configuration and form lithium cation with +1 charge.

[tex][Li^+]=1s^2[/tex]

Electronic configuration of bromine:

[tex][Br]=[Ar]3d^{10}4s^24p^5[/tex]

Bromine atom will gain one electron to gain noble gas configuration and form bromide ion with -1 charge.

[tex][Br^-]=[Ar]3d^{10}4s^24p^6[/tex]

In lithium bromide, one electron from lithium metal gets transferred to bromine atom.

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