Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Base on the question, which of the following that sates the balance of the reaction and as the aluminum loses 12 moles of electrons, what could be the oxygen, and base on my research, the possible answer among them is in number (2) gains 12 moles of electrons, I hope you are satisfied with my answer and feel free to ask for more
As aluminium loses 12 moles of electrons oxygen gain 12 moles of electrons.
Explanation
4Al + 3 O2→ Al2O3
first write the ions of Aluminium and oxygen
that is, Aluminium ion is = Al^3+
oxygen ion is = O^2-
therefore one atom of Al loses 3 electrons moles while
one atom of O gain 2 electrons moles
from equation above there a total of number of Al atom are 4 =( 1 x4=4) atoms while
Oxygen atoms are 6= ( 3 x2=6) atoms
therefore the total number of Moles of Al lost is = 3 x 4 = 12 moles of electrons
total number of moles of O gained = 2 x6 = 12 moles of electrons
Explanation
4Al + 3 O2→ Al2O3
first write the ions of Aluminium and oxygen
that is, Aluminium ion is = Al^3+
oxygen ion is = O^2-
therefore one atom of Al loses 3 electrons moles while
one atom of O gain 2 electrons moles
from equation above there a total of number of Al atom are 4 =( 1 x4=4) atoms while
Oxygen atoms are 6= ( 3 x2=6) atoms
therefore the total number of Moles of Al lost is = 3 x 4 = 12 moles of electrons
total number of moles of O gained = 2 x6 = 12 moles of electrons
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.