Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Solve the quadratic by factoring 2X²-2X-12=0

Sagot :

konrad509
[tex]2x^2-2x-12=0\\ 2(x^2-x-6)=0\\ 2(x^2-3x+2x-6)=0\\ 2(x(x-3)+2(x-3))=0\\ 2(x+2)(x-3)=0\\ x=-2 \vee x=3[/tex]
[tex]2x^2-2x-12=0\\\\2x^2+4x-6x-12=0\\\\2x(x+2)-6(x+2)=0\\\\(x+2)(2x-6)=0\iff x+2=0\ \vee\ 2x-6=0\\\\x=-2\ \vee\ x=3[/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.