lilianalaba
Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A tree casts a shadow 27 m long. At the same time, the shadow cast by a 66-cm tall statue is 56 cm long. Find the height of the tree to the nearest tenth of a meter?

Sagot :

iloveonedirection
[tex] \frac{height _{1} }{shadow_{1}} = \frac{height _{2} }{shadow_{2}} [/tex]

[tex] \frac{height _{1} }{27m} = \frac{66cm}{56cm} [/tex]

[tex]\frac{height _{1} }{2700cm} = \frac{66cm}{56cm}[/tex]

[tex]2700*66=56*h _{1} [/tex]

[tex]178200=56h _{1} [/tex]

[tex]3182.1cm=h _{1} [/tex]

[tex] \frac{3182.1cm}{1000cm} = 3.2m[/tex]

[tex]height:3.2m[/tex]
AL2006
As long as everything is on level ground with uniform elevation, and everything happens at the same time of day (with the sun at the same height in the sky) ... 

(66cm statue) / (56cm shadow) = (height of tree, meters) / (27m shadow)

Multiply each side of the equation by (27m) :

height of tree = (66 cm) x (27m) / (56cm) = 31.82 meters or 31.8 meters
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.