Answered

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let g(x)=x-3 and h(x)=x^2+6 find (h o g) (1)

Sagot :

konrad509
[tex]h \circ g=(x-3)^2+6=x^2-6x+9+6=x^2-6x+15[/tex]
kate200468
[tex]g(x)=x-3 \ \ \ and\ \ \ h(x)=x^2+6 \\\\(h \circ g) (1)=h\bigg (g(1)\bigg)=h\bigg(1-3\bigg)=h(-2)=(-2)^2+6=4+6=10[/tex]
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