Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

find the amplitude, period, and phase shift of the function defined by:
y=3-2cos(3x+pi)

Sagot :

AL2006
This is a sinusoidal wave with an amplitude of 2 , riding on a constant value of 3 .
The 3 isn't part of the function's amplitude ... the function wiggles between 2 under it
and 2 over it.

The period of the function is the change in 'x' that adds (2 pi) to the angle.

When x=0, the angle is pi

When the angle is (3 pi) . . .

3 pi = 3x + pi 
2 pi = 3x
x = 2/3 pi  The period of the function is 2/3 pi .

When x=0, the function is cos(pi) rather than cos(0).
So the function is a cosine with a phase shift of +pi.
It could also be described as a sine with a phase shift of -pi/2 or +3pi/2 .
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.