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Solve the inequality. 4(x – 3) – 2x ≥ 5 – (x + 2)

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konrad509
[tex]4(x - 3) - 2x \geq5 - (x + 2)\\ 4x-12-2x\geq5-x-2\\ 3x\geq15\\ x\geq5 [/tex]
[tex]4(x-3)-2x\geq5-(x+2)\\\\4x-12-2x\geq5-x-2\\\\2x-12\geq3-x\ \ \ \ /+12\\\\2x\geq15-x\ \ \ \ /+x\\\\3x\geq15\ \ \ \ /:3\\\\x\geq5\\\\x\in\left< 5;\ \infty\right)[/tex]
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