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determine whether (5,6) is the solution for y=x+1

Sagot :

iloveonedirection
[tex](5,6)[/tex]

[tex]x=5 \\ y=6[/tex]

[tex]y=x+1[/tex]

[tex](6)=(5)+1[/tex]

[tex]6=6[/tex]

[tex]true[/tex]
AL2006
Has your class not learned how to check an answer to see if it's correct ? ! ?

Your equation is [ y = x + 1 ].
You want to know whether (5, 6) is A solution to the equation.

When you write (5, 6), that means "x=5 and y=6".
So put those numbers into the equation in place of 'x' and 'y'
and see if the equation is true after you do that.

(y) = (x) + 1

(6) = (5) + 1

Do you see 5+1 on the right side.  That's 6.
So the equation says " 6 = 6 " . . . a true statement.
So (5, 6) is a solution of the equation.

It's not THE solution.  There are an infinite number of solutions
to that equation.  (5, 6) is one of them.
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