Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Need a step by step on how to solve this please

Need A Step By Step On How To Solve This Please class=

Sagot :

AL2006
I have not done this in advance.  I'm just going to write it down
and see what I can do with it:

[ 1/(x+3)² - 1/x² ] / 3


Multiply the top and bottom by (x+3)² :

[ 1 - (x+3)²/x² ] / 3 (x+3)²

Multiply the top and bottom by x² :

[ x² - (x+3)² ] / 3 x² (x+3)²

Now it's just a matter of expanding and cleaning things up,
and hope and pray that a lot of things cancel.

Eliminate the parentheses on top and bottom:

[ x² - x² - 6x -9 ] / 3 x² (x² + 6x + 9)

Combine the x² terms on top, and divide top and bottom by 3 :

[ - 2x - 3 ] / x² (x² + 6x + 9)

Finally, all I can make of this is:

- (2x + 3) / [ x(x+3) ]² .

That's not a whole lot prettier than the original form, but at least
we got rid of those fractions in the numerator of a fraction.

I hope this is some help to you.
[tex]\frac{\frac{1}{(x+3)^2}-\frac{1}{x^2}}{3}=\frac{1}{3(x+3)^2}-\frac{1}{3x^2}=\frac{x^2}{3x^2(x+3)^2}-\frac{(x+3)^2}{3x^2(x+3)^2}=\frac{x^2-x^2-6x-9}{3x^3(x+3)^2}\\\\=\frac{-6x-9}{3x^2(x+3)^2}=\frac{3(-2x-3)}{3x^2(x+3)^2}=-\frac{2x+3}{x^2(x+3)^2}[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.