Answered

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find X : log2+ logx=1

Sagot :

[tex]log2+logx=1;\ D:x\in\mathbb{R^+}\\\\log(2\ \cdot\ x)=log10\iff2x=10\ \ \ /:2\\\\x=5\in D\\\\Solution:x=5.[/tex]
konrad509
[tex]\log2+\log x=1\\ D:x>0\\ \log2x=1\\ 10^1=2x\\ 2x=10\\ x=5[/tex]
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