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What is the factoring quadratic expression for 27x^2-12=0

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konrad509
[tex]27x^2-12=0\\ 3(9x^2-4)=0\\ 3(3x-2)(3x+2)=0\\ x=\frac{2}{3} \vee x=-\frac{2}{3}[/tex]
kate200468
[tex] 27x^2-12=0\ /:3\\\\9x^2-4=0\ \ \ \Leftrightarrow\ \ \ (3x)^2-2^2=0\ \ \ \Leftrightarrow\ \ \ (3x-2)(3x+2)=0\\\\3x-2=0\ \ \ \ \ \ \ \ or\ \ \ \ \ \ 3x+2=0\\\\3x=2\ /:3\ \ \ \ \ \ \ or\ \ \ \ \ \ 3x=-2\ /:3\\\\x= \frac{2}{3} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ x=- \frac{2}{3} [/tex]
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