Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

If a grocery cart with a mass of 16.5 kg accelerates at +2.31 m/s2 against a frictional force of -15.0 N, what is the applied force?

Sagot :

Ryan2
2th Law of Newton:

[tex]\vec{R}=m.a\\ \\ \vec{R}=\vec{F} -\vec{F_a}=m.a\\ \\ \vec{F}-15=16.5*2.31\\ \\ \vec{F}=38.115+15\\ \\ \boxed{\vec{F}=53.115 \ N}[/tex]
AL2006
Call the applied force 'A'. (Clever ?)

The forces on the cart are  'A' forward and 15 N backward.

The net force on the art is (A-15) forward.

F = m a

Net forward force = (mass of the cart) x (its forward acceleration)

(A - 15) = (16.5) x (2.31)

A - 15 = 38.115

Add 15 to each side:

A = 53.115 newtons

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.