Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

If a grocery cart with a mass of 16.5 kg accelerates at +2.31 m/s2 against a frictional force of -15.0 N, what is the applied force?

Sagot :

Ryan2
2th Law of Newton:

[tex]\vec{R}=m.a\\ \\ \vec{R}=\vec{F} -\vec{F_a}=m.a\\ \\ \vec{F}-15=16.5*2.31\\ \\ \vec{F}=38.115+15\\ \\ \boxed{\vec{F}=53.115 \ N}[/tex]
AL2006
Call the applied force 'A'. (Clever ?)

The forces on the cart are  'A' forward and 15 N backward.

The net force on the art is (A-15) forward.

F = m a

Net forward force = (mass of the cart) x (its forward acceleration)

(A - 15) = (16.5) x (2.31)

A - 15 = 38.115

Add 15 to each side:

A = 53.115 newtons

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.