Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Actually, after the information you gave, I expected you to ask for the voltage
across the resistor, so I'm not quite sure what you mean by 'PD'. It could be the
"Potential Difference" or the "Power Dissipation" across the resistor.
Here are both answers:
Power Dissipation:
Power = Energy/time = 400 joules / 4 seconds = 100 joules/second = 100 watts.
Potential Difference (voltage):
Power dissipated by a resistor = (voltage)² / Resistance
100 watts = (voltage)² / 4 ohms
Multiply each side by 4 ohms:
400 watts-ohms = (voltage)²
Voltage = square root of 400 watts-ohms = 20 volts
across the resistor, so I'm not quite sure what you mean by 'PD'. It could be the
"Potential Difference" or the "Power Dissipation" across the resistor.
Here are both answers:
Power Dissipation:
Power = Energy/time = 400 joules / 4 seconds = 100 joules/second = 100 watts.
Potential Difference (voltage):
Power dissipated by a resistor = (voltage)² / Resistance
100 watts = (voltage)² / 4 ohms
Multiply each side by 4 ohms:
400 watts-ohms = (voltage)²
Voltage = square root of 400 watts-ohms = 20 volts
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.