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Please solve the equation
X^2+3x+3=0

Sagot :

AL2006
x² + 3x + 3 = 0

I can tell by looking that there's no easy way to factor the left side,
so we'll have to use the Quadratic formula.

Before doing that, let's just take a look at the discriminant:

( B² - 4AC ) = (9) - (4 x 3 x 1) = (9 - 12) = -3 .
The discriminant is negative, so we know that the roots will be complex conjugates.

Again:  x² + 3x + 3 = 0

x = (1/2) [ -3 plus or minus the square root of (-3) ]

x = -3/2 + (1/2) j√3
and
x = - 3/2 - (1/2) j√3
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