Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Given log 2 = 0.3010, log 3 = 0.4771. Find the value of a) log 12 b) log 5.

Sagot :

Pulkit
a) log 12 
= log3*4
= log3 + log4
=log3 + log 2^2
=log3 + 2log2
= 0.4771 +2*0.3010
=1.0791

b) log5
= log10/2
= log10 - log2
=1 - 0.3110
= 0.6989
kate200468
[tex]a)\ \ \ log12=log(4\cdot3)=log4+log3=log2^2+log3=2log2+log3\approx\\\\\approx2\cdot0.3010+0.4771=0.602+0.4771=1.0791\\\\2)\ \ \ log5=log \frac{10}{2} =log10-log2\approx1-0.3010=0.699[/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.