Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

The steamboat River Queen travels at the rate of 30km/h in still water. If it can travel 45 km up stream in the same amount of time that it takes to go 63 km down stream what is the rate of the current.

Sagot :

[tex]x-the\ rate\ of\ the\ current\\t-time\\\\ \left\{\begin{array}{ccc}(30-x)t=45\\(30+x)t=63\end{array}\right\\ \left\{\begin{array}{ccc}t=\frac{45}{30-x}\\t=\frac{63}{30+x}\end{array}\right\\\\\frac{45}{30-x}=\frac{63}{30+x}\\\\cross\ multiply\\\\63(30-x)=45(30+x)\\1890-63x=1350+45x\\-63x-45x=1350-1890\\-108x=-540\ \ \ \ /:(-108)\\x=5\\\\Answer:The\ rate\ of\ the\ current\ is\ 5\ km/h.[/tex]