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Sagot :
[tex]f(x)=2x-6\\
y=2x-6\\
2x=y+6\\
x=\frac{1}{2}y+3\\
f^{-1}(x)=\frac{1}{2}x+3\\
f^{-1}(2)=\frac{1}{2}\cdot2+3\\
f^{-1}(2)=1+3\\
f^{-1}(2)=4
[/tex]
a) Calculating f⁻¹(x)
[tex]y=2x-6\\ \\ x=2y-6\\ \\ 2y=x+6\\ \\ y=\frac{x+6}{2}\\ \\ \boxed{f^{-1}(x)=\frac{x+6}{2}}[/tex]
b) Calculating f⁻¹(2)
[tex]\boxed{\boxed{f^{-1}(2)=\frac{2+6}{2}=\frac{8}{2}=4}}[/tex]
[tex]y=2x-6\\ \\ x=2y-6\\ \\ 2y=x+6\\ \\ y=\frac{x+6}{2}\\ \\ \boxed{f^{-1}(x)=\frac{x+6}{2}}[/tex]
b) Calculating f⁻¹(2)
[tex]\boxed{\boxed{f^{-1}(2)=\frac{2+6}{2}=\frac{8}{2}=4}}[/tex]
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