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Can I have the formula to solve the algebra problem more easy 56x2+104x+48=0

Sagot :

[tex]56x^2+104x+48=0\\ 7x^2+13x+6=0\\ 7x^2+7x+6x+6=0\\ 7x(x+1)+6(x+1)=0\\ (7x+6)(x+1)=0\\ x=-\frac{6}{7} \vee x=-1[/tex]
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