Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
[tex]x^2-x-6=(x+2)(x-3)\\\\-x=2x-3x\\-6=2\times(-3)\\\\or\\\\x^2-x-6=x^2+2x-3x-6=x(x+2)-3(x+2)=(x+2)(x-3)[/tex]
I had a lot of trouble with this when my algebra class started doing it,
a long time ago.
The key is this: Look at the -6 at the end. You have to find two factors
of that number that add up to the -1 in the middle.
Here are the possible factors of -6 :
-1 ... 6
+1 ... -6
-2 ... 3
+2 ... -3
Can you find a pair on the list that adds up to -1 ?
How about +2 and -3 ?
Their product is -6 and their sum is -1. That's what you need.
Now set up a couple of binomial factors like this: (x....) (x....)
and write in the pair of numbers you found: (x + 2) (x - 3)
That's the factored form of the original expression.
a long time ago.
The key is this: Look at the -6 at the end. You have to find two factors
of that number that add up to the -1 in the middle.
Here are the possible factors of -6 :
-1 ... 6
+1 ... -6
-2 ... 3
+2 ... -3
Can you find a pair on the list that adds up to -1 ?
How about +2 and -3 ?
Their product is -6 and their sum is -1. That's what you need.
Now set up a couple of binomial factors like this: (x....) (x....)
and write in the pair of numbers you found: (x + 2) (x - 3)
That's the factored form of the original expression.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.