Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
[tex]sin30^o-sin45^ocos45^o\\\\sin30^o=\frac{1}{2}\\\\sin45^o=cos45^o=\frac{\sqrt2}{2}\\\\sin30^o-sin45^ocos45^o=\frac{1}{2}-\frac{\sqrt2}{2}\cdot\frac{\sqrt2}{2}=\frac{1}{2}-\frac{2}{4}=\frac{1}{2}-\frac{1}{2}=0\\\\Answer:a.[/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.