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Sagot :
10 = 2.5 ; 12 = 2².3 ; 126 = 2^4 ; 18 = 2.3²
the least common multiple is 2^4.5.3 = 240
then we have (2000 + x) = 240.k
2000 = 240.8 + 80 and 240.9 = 2160
then x = 160
the least common multiple is 2^4.5.3 = 240
then we have (2000 + x) = 240.k
2000 = 240.8 + 80 and 240.9 = 2160
then x = 160
Answer:
Number must be added = 160
Step-by-step explanation:
First we need to find LCM of 10,12,16 and 18.
LCM of 10,12,16 and 18 = 720
Let us write the multiplication table of 720
720, 1440, 2160, 2880 .................
We need to find the least number that must be added to 2000 so that the sum is divided exactly by 10,12,16 and 18 .
The number greater than 2000 is 2160.
Difference = 2160 - 2000 = 160
Number must be added = 160
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