Answered

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1 find the least number between 200 and 500 which leaves a reminder of 3 in each case when devided by 8,10,12 and 30

Sagot :

mariamikayla
x:8=c1 reminder 3
x=M₈ +3

x:10=c2 reminder 3
x=M₁₀ +3

x:12=c3 reminder 3
x=M₁₂ +3

x:30=c4 reminder 3
x=M₃₀ +3

x=[M₈;M₁₀;M₁₂;M₃₀]+3

8=2³
10=2* 5
12=2² * 3
30=2*3 *5

200 < x < 500

x= 2³ * 5 *3 +3
x=8*5*3+3
x=120+3
x=123 it doesn't corespond

x=2⁴ *15+3
x=16*15+3
x=240+3
x=243

x=8*5*9+3
x=40*9+3
x=360+3
x=363

x=8*5*3*4+3
x=40*12+3
x=480+3
x=483

x=8*5² *3+3
x=24*25+3
x=600+3
x=603  it doesn't corespond

x={243;363;483}
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