Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A chemist has one solution that is 80% acid and another solution that is 30% acid. How much of the first (80%) solution is needed to make a 400 L solution that is 62% acid?

Sagot :

Pulkit
Let x be the quantity of solution one in mixture.
so solution 2 would be (400-x) L

according to ques.
80% of x + 30% of (400-x) = 62% of 400
i.e. 80*x/100 + 30*(400-x)/100= 62*400/100
=> 80x - 30x = 62*400 - 30*400
=> 50x = 32*400
x=256 L
therefore 256L of solution one is required


Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.