Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Find the equation of the circle that passes through the origin and has its center at (-3,-4).

Sagot :

[tex]equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)\ is\ a\ cener\ of\ the\ circle\\\\(a;\ b)=(-3;-4)\\\\r-radius\ of\ the\ circle\\\\r=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\\\Answer:(x+3)^2+(y+4)^2=5^2\to(x+3)^2+(y+4)^2=25[/tex]
AL2006
If the center is at (-3, -4) and the origin is on the circle, then the radius
of the circle is the distance between the origin and (-3, -4).

R² = (-3)² + (-4)²
R² =  9    +  16
R² =      25
R = 5

The equation of the circle is [  (x + 3)² + (y + 4)² = 25 ].
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.