Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

What's perpendicular to:
y= x-1

And

y= -1/3x -1

Sagot :

[tex]k:y=m_1x+b_1;\ l:y=m_2x+b_@\\\\k\ \perp\ l\iff m_1m_2=-1\\\\========================\\k:y=x-1;\ l:y=mx+b\\\\k\ \perp\ l\iff1m=-1\to m=-1\\\\l:y=-1x+b\to y=-x+b\ (b\in\mathbb{R})\\==========================\\k:y=-\frac{1}{3}x-1;\ l:y=mx+b\\\\k\ \perp\ l\iff-\frac{1}{3}m=-1\to m=3\\\\l:y=3x+b\ (b\in\mathbb{R})[/tex]
AL2006
Those are two separate lines, and they're not parallel or perpendicular
to each other.
So there's no line that's perpendicular to both of them, and you're asking
two separate questions.

For both of them, you have to remember this: 
Lines that are perpendicular have negative reciprocal slopes.

-- The slope of [ y = x - 1 ] is 1, and the negative reciprocal of 1 is -1/1 = -1 .
A line perpendicular to [ y = x - 1 ] is [ y = -x + any number ].

-- The slope of [ y = -1/3 x - 1 ] is -1/3, and the negative reciprocal of -1/3 is 3 .
A line perpendicular to [ y = -1/3 x - 1 ] is [ y = 3x + any number ].


Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.