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If the product of a number and -8 is subtracted from the number, the result is 7 more than the number. find the number. Use x for the number.
x-(-8x)=


Sagot :

[tex]x-(-8\cdot x)=x+7\\\\x-(-8x)=x+7\\\\x+8x=x+7\\\\9x=x+7\\\\9x-x=x+7-x\\\\8x=7\\\\8x:8=7:8\\\\x=\frac{7}{8}[/tex]
AL2006
You have said that  [  x - (-8x) = x + 7  ] .

Note that  [ - (-8x) ] = 8x

So the equation may be written as  [  x + 8x = x + 7  ] .

Add up the 'x's on the left side:            9x = x + 7

Subtract 'x' from each side:                  8x = 7

Divide each side by 8 :                        x = 7/8