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Sagot :
Remember:
[tex]3\frac{3}{4}=\frac{15}{4}[/tex]
Area of a triangle
[tex]A=\frac{1}{2}.b.h\\ \\ A=\frac{1}{2}*5*\frac{15}{4}=\frac{75}{8}=9\frac{3}{8} \ in^2[/tex]
[tex]3\frac{3}{4}=\frac{15}{4}[/tex]
Area of a triangle
[tex]A=\frac{1}{2}.b.h\\ \\ A=\frac{1}{2}*5*\frac{15}{4}=\frac{75}{8}=9\frac{3}{8} \ in^2[/tex]
[tex]Area= \frac{bh}{2}
\\ \\ 5*3.75=18.75
\\ \\ \frac{18.75}{2} = 9.375
\\\\\boxed{9.375}[/tex]
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