Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The volume of a cylinder with flat ends is (pi) x (radius squared) x (length) .
Radius of the tank = 1/2 diameter = d/2.
Volume = (pi) x (d/2)² x (height)
Height = ( V ) / ( pi x d²/4 )
Height = ( 4V ) / ( pi d² )
Radius of the tank = 1/2 diameter = d/2.
Volume = (pi) x (d/2)² x (height)
Height = ( V ) / ( pi x d²/4 )
Height = ( 4V ) / ( pi d² )
In this exercise we have to use the volume knowledge to calculate the size of the tank, like this:
[tex]H= ( 4V ) / ( \pi d^2)[/tex]
Then, recalling the formula for the volume of the cylinder, we find that:
[tex]volume= (\pi) * (radius \ squared) * (length)[/tex]
And we know some information like:
- Radius of the tank = 1/2
- diameter = d/2
In this way we find that:
[tex]Volume = (\pi) * (d/2)^2 * (height)\\Height = ( V ) / ( \pi * d^2/4 )\\Height = ( 4V ) / ( \pi d^2)[/tex]
See more about volume at brainly.com/question/1578538
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.