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Find 3 consecutive even numbers where the product of the smaller two numbers is 40 less than the square of the largest number.

Sagot :

luana
[tex]3\ consecutive\ even\ numbers:\ 2x,2x+2,2x+4\\\\2x(2x+2)+40=(2x+4)^2\\\\ 4x^2+4x+40=4x^2+16x+16\\\\ 4x^2-4x^2+4x-16x=16-40\\\\-12x=-24\ \ |:(-12)\\\\x=\frac{24}{12}=2\\\\2x=2=4\\\\2x+2=6\\\\2x+4=8\\\\Numbers\ are\ 4,6,8.[/tex]
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