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Sagot :
The speed of one car is 'S'. The speed of the other car is (S + 10).
In 5 hours, the first car travels (5S) miles, and the other car travels 5(S + 10) miles.
Since they're going in opposite directions, the distance between them at any time
is the sum of the distance that each one has traveled.
500 = (5S) + 5(S + 10)
500 = 5S + 5S + 50
500 = 10S + 50
Subtract 50 from each side:
450 = 10S
Divide each side by 10
S = 45
S + 10 = 55
In 5 hours, the first car travels (5S) miles, and the other car travels 5(S + 10) miles.
Since they're going in opposite directions, the distance between them at any time
is the sum of the distance that each one has traveled.
500 = (5S) + 5(S + 10)
500 = 5S + 5S + 50
500 = 10S + 50
Subtract 50 from each side:
450 = 10S
Divide each side by 10
S = 45
S + 10 = 55
Let one car travel at x mph
The other car travels at x+10 mph
Their combined speed is 2x+10 mph.
Distance = 500
time = 500 /2x+10 =5
10x+50=500
10x= 450
x=45 speed of one car
The other car travels at 45+10 = 55 mph
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