Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Two cars leave Denver at the same time and travel in opposite directions. One car travels 10 mi/h faster than the other car. The cars are 500 mi apart in 5 h. How fast is each car traveling?

Sagot :

AL2006
The speed of one car is 'S'.  The speed of the other car is (S + 10).

In 5 hours, the first car travels (5S) miles, and the other car travels  5(S + 10) miles.

Since they're going in opposite directions, the distance between them at any time
is the sum of the distance that each one has traveled.

500 = (5S) + 5(S + 10)

500 = 5S  +  5S + 50

500 = 10S + 50

Subtract 50 from each side:

450 = 10S

Divide each side by 10

S = 45

S + 10 = 55
teehartinegr

Let one car travel at x mph

The other car travels at x+10 mph

Their combined speed is 2x+10 mph.

Distance = 500

time = 500 /2x+10 =5

10x+50=500

10x= 450

x=45 speed of one car

The other car travels at 45+10 = 55 mph

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.