Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

The perimeter of a square is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot, what is the area, in square feet, of the new figure

Sagot :

BRVR
The square before the transformation would have side lengths of 5 since 5*4=20
so increasing the length and decreasing the width would make the square a rectangle with dimensions 7×4.
a=LW
a=(7)(4)
=28ft²
AL2006
All 4 sides of a square are the same length.
If the perimeter of the square is 20-ft, then each side is 20-ft/4 = 5 ft.

If you increase the length of the square by 2-ft, then its new length is 5+2 = 7-ft.
 
If you decrease the width of the square by 1-ft, then its new width is 5-1 = 4-ft.

The area of the new figure is (length) x (width) = (7-ft x 4-ft) = 28 square feet.
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.