Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

The perimeter of a square is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot, what is the area, in square feet, of the new figure

Sagot :

BRVR
The square before the transformation would have side lengths of 5 since 5*4=20
so increasing the length and decreasing the width would make the square a rectangle with dimensions 7×4.
a=LW
a=(7)(4)
=28ft²
AL2006
All 4 sides of a square are the same length.
If the perimeter of the square is 20-ft, then each side is 20-ft/4 = 5 ft.

If you increase the length of the square by 2-ft, then its new length is 5+2 = 7-ft.
 
If you decrease the width of the square by 1-ft, then its new width is 5-1 = 4-ft.

The area of the new figure is (length) x (width) = (7-ft x 4-ft) = 28 square feet.
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.