Gracelux
Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Find all zeros (real and complex) for the function f(x)=x^3-5x^2+9x-5

Sagot :

konrad509
[tex]f(x)=x^3-5x^2+9x-5\\ f(x)=x^3-x^2-4x^2+4x+5x-5\\ f(x)=x^2(x-1)-4x(x-1)+5(x-1)\\ f(x)=(x-1)(x^2-4x+5)\\\\ (x-1)(x^2-4x+5)=0\\\\ x-1=0\\ x=1\\\\ x^2-4x+5=0\\ x^2-4x+4+1=0\\ (x-2)^2=-1\\ x-2=i \vee x-2=-i\\ x=2+i \vee x=2-i\\\\ x=\{1,2-i,2+i\} [/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.